(200x)/((10^2+x^2)^1/2)-160

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Solution for (200x)/((10^2+x^2)^1/2)-160 equation: 


D( x )

((x^2+10^2)^1)/2 = 0

((x^2+10^2)^1)/2 = 0

((x^2+10^2)^1)/2 = 0

(x^2+10^2)/2 = 0

(x^2+100)/2 = 0

1*x^2 = -100 // : 1

x^2 = -100

x in (-oo:+oo)

(200*x)/(((x^2+10^2)^1)/2)-160 = 0

(200*x)/((x^2+10^2)/2)-160 = 0

(2*200*x)/(x^2+100)-160 = 0

(2*200*x)/(x^2+100)+(-160*(x^2+100))/(x^2+100) = 0

2*200*x-160*(x^2+100) = 0

400*x-160*x^2-16000 = 0

400*x-160*x^2-16000 = 0

80*(5*x-2*x^2-200) = 0

5*x-2*x^2-200 = 0

DELTA = 5^2-(-200*(-2)*4)

DELTA = -1575

DELTA < 0

80 = 0

80/(x^2+100) = 0

80/(x^2+100) = 0 // * x^2+100

80 = 0

x belongs to the empty set

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